Writing Equations in Point-Slope & Slope-Intercept

For each line, use the given conditions to write an equation in the point- cant over form and the slope-intercept form. i.Slope = 4, passing through (1, 3) purpose slope: y-3=4(x-1) (y-3)+(-4(x-1)=4(x-1)+(-4(x-1)) y-(4x-4)-3=4(x-1)-4(x-1) (y-4x+1)+(4x-1)=4x-1 y=4x-1 Slope-intercept: y-3=4(x-1) y-3=4x-4 y+1=4x x=y+1/4 0=y+1/4 0=y+1 -1=y (0,-1) ii.Slope = 8, passing through (4, 1) Point slope: y-(-1)=8(x-4) (y-(-1))+(-8(x-4))=8(x-4)+(-8(x-4)) y-(8x-32)+1=8(x-4)-8(x-4) (y-8x+33)+(8x-33)=8x-33 Y=8x-33 Slope-intercept: y-(-1)=8(x-4) y+1=8x-8*4 y+33=8x x=y+33/8 0=y+33/8 0=y+33 -33=y (0,-33) iii.

Slope = 5, passing through (4, 2) Point slope: y-(-2)=(-5)(x-(-4)) y+(5x+20)+2=(-5)(x+4)+(-(-5)(x+4)) (y+5x+22)+(-5x-22)=-5x-22 y=-5x-22 Slope-intercept: y-(-2)=(-5)(x-(-4)) y+2=-(5x+20) y+22=-5x x=-y+22/5 0=-y+22/5 0=y+22 -22=-y-44 y+44=22 y=-22 iv.Slope = 2, passing through (0, 3) Point slope: y-(-3)=(-2)(x-0) (y-(-3))+(-(-2)(x))=(-2)(x)+(-(-2)(x)) (y+2x+3)+(-2x-3)=-2x-3 y=-2x-3 Slope-intercept: y-(-3)=(-2)(x-0) x=y+3/2 0=-y+3/2 0=y+3 -3=-y-6 -(y+6)=-3 y+6=3 y=-3 (0,-3) carbon% Excellent work! Good job writing equations in point-slope and slope-intercept form If you want to get a full essay, graze it on our website: Orderessay

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